Don't Take My Word For It (Part 1): Getting the type dynamically

Ever wanted to know what type something is in C++, but your editor can’t or won’t tell you (or you don’t trust it…?) You’ve probably been in some templated function, nested a few levels deep, gone to get a coffee, come back and forgotten quite how it fits together and asked yourself “what exactly is T anyway”? Don’t take my word or anyone else’s - If in doubt, ask the compiler (or the runtime).

In Python we’re used to doing simply

>>> type("foo")
<class 'str'>

Types are objects. type(some_object) returns an object that happens to be the type of some_object. Since that type is itself an object, you can print it. Informative and helpful.

No such luck in C++: types are not objects. If you try to do std::cout << std::string you’ll get an angry compiler (std::string is not an object, it’s a type, so you can’t just pass it to some overload of operator<<).

A bit of Googling later, you might come across the typeid operator which returns a std::type_info object, which has a name() function. So far this appears pretty helpful. Giving it a test drive:

#include <iostream>
#include <typeinfo>

int main ()
  const auto c_string = "foo";
  const auto cpp_string = std::string ("foo");

  // What's the type of c_string?
  std::cout << typeid(c_string).name() << '\n';

  // What's the type of cpp_string?
  std::cout << typeid(cpp_string).name() << '\n';

Possible output (compiler explorer) if you use gcc:


There’s something there, but you wouldn’t call it easy to read! And we’re already firmly into implementation-defined behaviour. You’ll get something else that might be more-or-less readable. At least the second bit at least has the word “string” in it.

Fortunately for gcc users you can demangle this (yes that’s a technical term) with a command-line tool:

$ c++filt -t PKc
char const*
$ c++filt -t NSt7__cxx1112basic_stringIcSt11char_traitsIcESaIcEEE
std::__cxx11::basic_string<char, std::char_traits<char>, std::allocator<char> >

With gcc it’s also possible to do this on the fly in C++ (see a nice SO answer here), but this is strictly vendor-specific.

So we’ve got something that works, on one compiler at least, and with a little bit of effort prints out the type of a variable. Well, not quite… typeid actually gives you the type of an expression. It doesn’t have the special fudge decltype has, wherein decltype(x) means “the type of x” and anything that isn’t just a variable name, such as decltype((x)), means “the type of the expression”.

In our case, both variables should have a top-level const (i.e. char const * const and const std::string) but typeid loses the top-level qualifier for us.

I’m a stranger to the Windows programming world, but I downloaded Visual Studio Community 2022 and ran the same program - here’s the output:

char const * __ptr64
class std::basic_string<char,struct std::char_traits<char>,class std::allocator<char> >

Actually quite helpful! It still loses the top-level const on the string (that’s inevitable because that’s how typeid works) but at least it doesn’t need decoding.

There’s another use for typeid that we haven’t covered here but deserves a mention: it can be used for RTTI purposes. If you’ve got a base class Base and one or more derived classes (and you’ve remembered your virtual destructor in the base class), typeid can tell you which derived class a reference-to-base refers to:

#include <iostream>
#include <typeinfo>

struct Base
  virtual ~Base() {};

struct D1 : Base {};
struct D2 : Base {};

int main ()
  D2 derived;
  Base &ptr_to_base = derived;

  std::cout << std::boolalpha;
  std::cout << (typeid (ptr_to_base) == typeid (D1)) << '\n';
  std::cout << (typeid (ptr_to_base) == typeid (D2)) << '\n';

Output (compiler explorer):


So far we’ve looked at the uses of typeid. In Part 2 we will use a trick to work out mystery types using compiler error messages.